x^2+2x-365^2=0

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Solution for x^2+2x-365^2=0 equation:



x^2+2x-365^2=0
We add all the numbers together, and all the variables
x^2+2x-133225=0
a = 1; b = 2; c = -133225;
Δ = b2-4ac
Δ = 22-4·1·(-133225)
Δ = 532904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{532904}=\sqrt{4*133226}=\sqrt{4}*\sqrt{133226}=2\sqrt{133226}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{133226}}{2*1}=\frac{-2-2\sqrt{133226}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{133226}}{2*1}=\frac{-2+2\sqrt{133226}}{2} $

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